Hello friends, In this post, I’m giving you my solution to the CS50 problem set 1 cash problem. So in this program, we have to implement a solution that prompts users for the number of cents that a customer is owed and prints the smallest number of coins with which that change can be made.

The main function is already implemented for us. The following code shows how I resolve this problem, Hope it helps you!

```
#include <cs50.h>
#include <stdio.h>
int get_cents(void);
int calculate_quarters(int cents);
int calculate_dimes(int cents);
int calculate_nickels(int cents);
int calculate_pennies(int cents);
int main(void)
{
// Ask how many cents the customer is owed
int cents = get_cents();
// Calculate the number of quarters to give the customer
int quarters = calculate_quarters(cents);
cents = cents - quarters * 25;
// Calculate the number of dimes to give the customer
int dimes = calculate_dimes(cents);
cents = cents - dimes * 10;
// Calculate the number of nickels to give the customer
int nickels = calculate_nickels(cents);
cents = cents - nickels * 5;
// Calculate the number of pennies to give the customer
int pennies = calculate_pennies(cents);
cents = cents - pennies * 1;
// Sum coins
int coins = quarters + dimes + nickels + pennies;
// Print total number of coins to give the customer
printf("%i\n", coins);
}
int get_cents(void)
{
int cents;
do {
cents = get_int("Change Owed: ");
} while (cents < 0);
return cents;
}
int calculate_quarters(int cents)
{
int quarters = cents / 25;
return quarters;
}
int calculate_dimes(int cents)
{
int dimes = cents / 10;
return dimes;
}
int calculate_nickels(int cents)
{
int nickels = cents / 5;
return nickels;
}
int calculate_pennies(int cents)
{
int pennies = cents / 1;
return pennies;
}
```

**You may also like to read: The solution to CS50 Psets 2 Caesar Problem (2022)**

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